00:01
So given this limit, let's just use the method of replacement.
00:03
Replace all the x values that i have with 7, see what limit i get.
00:10
So 7 squared minus 2 times 7 minus 25.
00:14
Okay.
00:15
This will end up being 49 minus 14.
00:21
And we know that 49 minus 14 is 35 minus 25 minus 25 will be positive 10.
00:29
Okay, all over 7 times 7 minus 7 squared.
00:36
7 squared minus 7 squared, this is going to be 0.
00:40
But note that, oh, excuse me, this is 35.
00:50
So then this will also be 0.
00:53
Okay, so i have in the terminate form, 0 divided by 0...