Question

Problem #1 The 4.0 inches stroke of a pneumatic cylinder which has a cross sectional area of 10.0 square inches is filled by air at standard pressure. The air inside the cylinder is compressed by a piston to 28.0 psi at constant temperature. Find the volume of the air inside the cylinder. Problem #2 A 30 cubic inches volume of air at temperature of 78 degree F is expanded at constant pressure until the temperature increases to 200 degree F. Find the new volume of the gas. Problem # 3 A gas occupying a volume of 200 cubic inches at 68 degree F and standard pressure is expanded to a new volume of 300 cubic inches. The pressure is then found to be half of the atmospheric pressure. What is the final temperature of the air? Problem #4 Gas at 1000. psig and 100 degree F is contain in the 2000 cubic inches cylinder. A piston compresses the volume to 1500 cubic inches, While the gas is heated to 200 degree F. What is the final pressure in the cylinder.

          Problem #1
The 4.0 inches stroke of a pneumatic cylinder which has a cross
sectional area of 10.0 square inches is filled by air at standard
pressure. The air inside the cylinder is compressed by a piston to
28.0 psi at constant temperature. Find the volume of the air inside
the cylinder.
Problem #2
A 30 cubic inches volume of air at temperature of 78 degree F is
expanded at constant pressure until the temperature increases to
200 degree F. Find the new volume of the gas.
Problem # 3
A gas occupying a volume of 200 cubic inches at 68 degree F and
standard pressure is expanded to a new volume of 300 cubic inches.
The pressure is then found to be half of the atmospheric pressure.
What is the final temperature of the air?
Problem #4
Gas at 1000. psig and 100 degree F is contain in the 2000 cubic
inches cylinder. A piston compresses the volume to 1500 cubic
inches, While the gas is heated to 200 degree F. What is the final
pressure in the cylinder.

Show more…

Problem #1
The 4.0 inches stroke of a pneumatic cylinder which has a cross
sectional area of 10.0 square inches is filled by air at standard
pressure. The air inside the cylinder is compressed by a piston to
28.0 psi at constant temperature. Find the volume of the air inside
the cylinder.
Problem #2
A 30 cubic inches volume of air at temperature of 78 degree F is
expanded at constant pressure until the temperature increases to
200 degree F. Find the new volume of the gas.
Problem # 3
A gas occupying a volume of 200 cubic inches at 68 degree F and
standard pressure is expanded to a new volume of 300 cubic inches.
The pressure is then found to be half of the atmospheric pressure.
What is the final temperature of the air?
Problem #4
Gas at 1000. psig and 100 degree F is contain in the 2000 cubic
inches cylinder. A piston compresses the volume to 1500 cubic
inches, While the gas is heated to 200 degree F. What is the final
pressure in the cylinder.

Added by Linda A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

05/25/2023

Step 1

0 inches Cross-sectional area = 10.0 square inches Initial pressure = Standard pressure = 14.7 psi Final pressure = 28.0 psi Temperature = Constant To find: Volume of air inside the cylinder Solution: We know that the volume of the cylinder is given by: Volume = Show more…

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Transcript

00:01 Hi, this is a question based on ideal gas.

00:04 So here we are given with a volume v is equal to so we have volume v is 4 inch.

00:10 So length is 4 inch so volume will be equal to 4 inch cube.

00:14 So 40 inch cube then we have so then we have the atmospheric pressure is given as so atmospheric is 40 .70 pounds per inch square and we have the pressure p1 will be 40 .70 then we have by ideal gas equation p1 v1 is equal to p2 v2 so we have 14 .70 into 40 which is equal to p2 into v2.

00:46 So, we have v2 volume is equal to so 14 .70 into 40 divided by 28 which is equal to 2 inch cube.

00:59 In the second part we are given with a volume v1 is equal to 30 inch cube and we have the temperature t1 is given as 78 degree fahrenheit.

01:08 So it is converted to rankine that is added by 459 .67 we have the temperature t1 is 537 .67 r and we have the temperature t2 is given as 200 degree fahrenheit which is equal to 659 .67 degree rankine.

01:25 So we have to find the volume 2 so we have p1 v1 is equal to t1 and p2 v2 is equal to t2.

01:35 So, taking the ratio we have v1 by v2 is equal to t1 by t2.

01:40 So by this we have so we have the volume of v1 is given as 30 inch cube and we have temperature t1 and t2.

01:49 So by this calculation we have v2 is equal to 36 .807 inch cube.

01:57 In the next part of the question we have p1 is given by 14 .70 and v1 is given as 200 inch cube.

02:07 So t1 is 527 .67 degree rankine.

02:11 So we have so we have pressure p1 or pressure p2 is half of the pressure p1...

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