00:01
First of all, let's have a look what all is given in the problem.
00:04
Given is we need to propose the structures.
00:08
Now what all is given? hydrocarbon with seven lines.
00:16
Hydrocarbon with seven lines.
00:21
Seven lines in 13 cnmr.
00:25
And the second one is given as six carbon compound, six carbon compound with only five lines.
00:35
With 5 lines in 13 c nmr and the last part is 4 carbon compound with 3 lines in 13 c nmr with 3 lines in 13 c nmr and what we are supposed to find out we have to find the structures for all these we need to draw the structures for all the 3 so, first of all, in first one, only seven lines are coming and it is a hydrocarbon in 13c nmr, we are getting only seven lines.
01:30
In other words, we can say that we need a carbon compound with seven carbons unique in it, with seven unique carbons present in it.
01:41
Then only it will give seven lines.
01:45
So, let's draw a carbon compound having 30.
01:50
Carbon because in that it will have a plane of symmetry.
01:54
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 11, 12 and 13.
02:04
1, 2, 3, 4, 5, 6, 7...