$$\sum_{i=0}^{0} \binom{0+1}{i+1} = \binom{1}{1} = 1$$
$$2^0 = 1$$
Since both sides are equal, the base case holds.
Inductive Step:
Assume the statement is true for n, i.e.,
$$\sum_{i=0}^{n} \binom{n+1}{i+1} = 2^n$$
We want to show that the statement is true for
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