What is the value of ( frac{d y}{d x} ) at the point ( P(1,0) ) for the curve ( y=y(x) ) given by [ cos left(y^{2} ight)+y^{3}+x^{2}+4 x y=2 ? ] (a) -4 (b) -2 (c) -1 (d) ( -frac{1}{2} ) (e) ( -frac{1}{4} )
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Using the chain rule and product rule, we get: $-\sin(y^2) \cdot (2yy') + 3y^2y' + 2x + 4y + 4xy' = 0$ Show more…
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