00:01
In this problem, we are given an implicit equation relating y and x.
00:06
We want to find the value of dy over dx at the point x equal to 1 and y equal to 0.
00:13
So what we're going to do here is we're going to differentiate implicitly with respect to x.
00:21
So on the left hand side, we will have the derivative of cos of y squared plus y cubed plus x squared plus 4 times xy.
00:36
And on the right hand side, we will have the derivative of the constant 2.
00:43
And as we know, the derivative of all constants are equal to 0.
00:48
So this right hand side will simply be equal to 0.
00:50
So let's develop this left hand side, being careful to utilize chain rule when necessary.
00:56
So first, let's differentiate cos of y squared.
01:00
The derivative of cos is minus sine.
01:05
And now we differentiate the interior derivative of x squared, giving us 2y.
01:13
And let's not forget dy over dx due to chain rule...