Que cantidad de calor que debe absorber 900 kg de agua cuando se calienta desde 25°C hasta 95°C? Exprese su resultado en calorias (cal) a. 1.8 x 10^8 cal b. 2.64 x 10^8 cal c. 1.31 x 10^8 cal d. 6.31 x 10^7 cal
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The initial temperature is 25°C and the final temperature is 95°C. So, the change in temperature is: ΔT = final temperature - initial temperature ΔT = 95°C - 25°C ΔT = 70°C Show more…
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