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. An ice-cube tray contains 0.350 $\mathrm{kg}$ of water at $18.0^{\circ} \mathrm{C}$ . How much heat must be removed from the water to cool it to $0.00^{\circ} \mathrm{C}$ and freeze it? Express your answer in joules and in calories.

$\begin{aligned} Q_{\text { removed }} &=-1.43 \times 10^{5} \mathrm{J} \\ Q_{\text { removed }} &=3.42 \times 10^{4} \mathrm{cal} \\ Q_{\text { remored }} &=135.5 \mathrm{Btu} \end{aligned}$

Physics 101 Mechanics

Chapter 14

Temperature and Heat

Thermal Properties of Matter

The First Law of Thermodynamics

Rutgers, The State University of New Jersey

Hope College

University of Sheffield

Lectures

02:20

A solid, liquid, or gas is one of the three main states of matter. Solids have a definite shape and volume, and retain their shape when a force is applied to them. They are rigid, and do not flow to take on the shape of a container, but retain their own shape. Solids are held together by intermolecular forces, which are usually chemical bonds. Liquids have a free-flowing, continuous surface, and take the shape of a container. They flow to fill an available space. Their particles do not have a definite shape or volume, and they are not rigid. Gases have no definite shape or volume. They are not held together, and are not rigid. They flow to fill an available space. Gases are often described as being the state of matter with the lowest density.

03:25

The First Law of Thermodynamics is an expression of the principle of conservation of energy. The law states that the change in the internal energy of a closed system is equal to the amount of heat energy added to the system, minus the work done by the system on its surroundings. The total energy of a system can be subdivided and classified in various ways.

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An ice-cube tray of neglig…

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An ice-cule tray of neglig…

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How much heat is required …

02:34

How much heat, in joules a…

01:16

How much heat must be remo…

01:07

How many joules of heat mu…

Guys, let's take a look at the question, so the question was asking us for a the amount of heat okay. So when q, in these cases, mc dot, t plus ml mc dotter is the p required to change the temperature? And here tis here is the latent heat altogether. Why we need to write on heat here is because it's from 18 degrees to drop to 0 degrees, so a 0 degree there's the face trance transmission from dequato solid. So we need the later heat getting both in this question. We know the absolute value for delta t is 0 degree, minus 18 degrees, which is 18 degrees celsius and the later heats for eyes, which is the water at 0 degree. Celsius is 334 times 10 to the power 3 ju per kilogram, and the mass of the water is 0.350 kilograms. So now we can figure out q, because q is just simply equal to m, which is 0.350 kilograms times c, and the specific heat of water is 4192 per kilogram times. Degrees celsius test the change in temperature, which is 18 degrees celsius and well, that's simplify it. So you will be just suntingwhich: is the plus de latentis, 334 times 10 to the power over 3 jou per kilogram? Okay, why? The idea is, i will tell you why you see here is m c times delta, t plus ml. If we take ml will just give us, q equals to m times c delta, t plus lay, and that's why i set up q, equals to something like this ay and let's work our calculations. Okay, so eventually q will be equal to 1.43 times 10 to the power 5 runned up. You might have a son answered like 4697 point, so i wind to the 1000 digits and you give us 1.43 times, 10 to 5 and in calories, that's about. Let me see that's about 3.42 and you see 3.42 times 10 to the power 4 calories. Okay and that's the answer for these questions. Thank you.

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