00:01
Let's take a look at the question.
00:01
The question was asking us for the amount of heat.
00:06
So, q, in this case, is equal to mc dota plus ml.
00:12
Mc dl here is the heat required to change the temperature.
00:16
And m here, m plus l here is the latent heat altogether.
00:21
Why we need the latent heat here is because it's from 18 degree to drop to 0 degree.
00:30
At 0 degree, there is the phase transmission from liquid to solid.
00:39
So we need a later heat to get involved in this question.
00:42
We know the absolute value for delta t is 0 degree minus 18 degrees, which is 18 degrees celsius.
00:50
And the later heat for ice, which is the water at 0 degree celsius, is 334 times 10 .2 power 3 jr per kilometer.
01:00
And the mass of the water is 0 .350 kilogram.
01:06
So now we can figure out q.
01:09
Because q is just simply equal to m, which is 0 .350 kilograms times c.
01:24
And the specific heat of water is 4190 per kilogram times degrees celsius.
01:35
Okay? times the changing temperature, which is 18 degrees celsius.
01:46
And well, let's simplify it...