00:01
We have a mass of water to be 0 .290 kilograms, and its original temperature is 18 degrees celsius, and we want to know how much heat must be removed to freeze this water.
00:15
And so the temperature final will be 0 degrees celsius.
00:18
And so our change in temperature is 0 minus 18, which gives us negative 18 degrees celsius.
00:25
We know the latent heat of fusion for water to be 334 times.
00:30
10 to the 3 joules per kilogram, and the specific heat to be 4 ,190 joules per kilogram kelvin.
00:41
And so we're going to use the equation where heat, energy, loss, or gain is equal to mass times specific heat, change, and temperature, and because there is a phase change minus the energy for that phase change.
00:55
And so we plug in the information we know now.
00:58
So we have 0 .29 times 4 ,190 times negative 18 minus 0 .29 times 0 .29 times 3 .34 times 10 to the 3.
01:13
And so we're going to get negative 21 ,871 .8 minus 96860.
01:25
And when we put these together, we get negative 11 ,8171 .7 .1 .3.
01:30
And when we put these together, we get negative 1 .8 joules.
01:32
And we're going to put this into scientific notation to make it a little bit easier to understand...