Question
An ice-cube tray of negligible mass contains 0.290 kg of water at 18.0$^\circ$C. How much heat must be removed to cool the water to 0.00$^\circ$C and freeze it? Express your answer in joules, calories, and Btu.
Step 1
0$^\circ$C to 0.00$^\circ$C. The formula for this is $Q = mc\Delta T$, where $m$ is the mass of the water, $c$ is the specific heat capacity of water, and $\Delta T$ is the change in temperature. Show more…
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