00:01
From the given quotient, we have a graph here.
00:03
Now you need to evaluate double integral d, n divided by a, y, d ,a.
00:13
Now from the graph, minus 1, less than are equal to y is equal to less than are equal to 0, right side, curve, x is equal to y minus y cube, and, left side curve x is equal to minus 1 and second one is 0 less than are equal to y less than are equal to 1 so here right side curve x is equal to y minus y cube and left side curve x is equal to y minus y cube and left side curve x is equal to y minus 1 now the question double d, y, d, a is equal to integral minus 1 to 0, integral minus 1 to 1 to, y minus y cube, y, d x, dy, plus integral 0 to 1, integral, y minus 1 2, y, minus, y, qib, y, d x, dx, d, that is equal to we can write it as integral minus 1 to 0 y of x minus 1d.
01:56
Y minus y minus y cube d y plus integral 0 to 1 y half x y minus y cube d y that is equal to we can write it as integral minus 1 to 0 y square minus y power 4 plus y d y plus integral 0 to 1 y minus y power 4 d y now we can write it as y cube divided by 3 minus 1 minus 1 to 0 0 minus y power 5 divided by 5 minus 1 to 0 plus y squared divided by 2 minus 1 to 0 to 1.
03:02
Plus y squared divided by 2 0 to 1 minus y power 5 divided by 5 0 to 1...