00:01
In this question, we are asked to find the power series for the given function centered at 0 and find the interval of convergence.
00:08
And we will start with the formula for 1 over 1 minus u, which equals to the series u to the n, n from 0 to infinity.
00:18
This series converges for the absolute value of u less than 1.
00:23
Next, we will rewrite the function x, f as x multiplied by 1 over 1 minus negative 3x.
00:31
Now, if we take u to be equal to negative 3x, after plugging in negative 3x in this formula, we will get x multiplied by the series negative 3x to the nth power, n from 0 to infinity.
00:56
This equals to the series negative 3 to the n multiplied by x to the n plus first power, n from 0 to infinity.
01:08
Now, let's write down the first few terms of the series.
01:11
For n equals 0, we will get x.
01:17
For n equals 1, it's going to be minus negative 3 multiplied by x squared...