Find the derivative of the function. f(x) = cos^2(sin^2 x) f'(x) = 2 sin x cos x f'(x) = -sin(2 sin^2 x) sin(2x) f'(x) = -2 cos(sin^2 x) sin(sin^2 x) f'(x) = 2 cos(2 sin x)
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In this case, we have the function f(x) = cos(2sinx). Show more…
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