00:01
So, we have given here the function minimum of z is equal to 2x1 plus 3x2 and subject to constants are 4x1 plus 6x2 is greater than equal to 6.
00:26
Next is 2x1 plus 2x2 is less than equal to 4 and x1 comma x2 is greater than equal to 0.
00:41
So, first we have equation that is 4x1 plus 6x2 is greater than equal to and we need to write here is equal to is equal to 0 is equal to 6.
01:01
So, our equation become x1 upon we need to write this intercept form 3 by 2 plus x2 upon 1 is equal to 1.
01:13
So, let's say this is our equation number first.
01:16
Second equation we have here 2x1 plus 2x2 is equal to 4.
01:25
So, from here we can write that is x1 upon 2 plus x2 upon 2 is equal to 1.
01:37
So, let's say this is our equation number second.
01:40
So, if we so if we draw the graph so our graph makes approximate let's say this is our a point and this is our b point.
01:51
A point is we have here let's say and that is 3 by 2 comma 0.
02:12
B point let's say we have here 2 comma 0 after solving equation number first and second.
02:20
C point we have here 0 comma 2.
02:24
D point we have here 0 point 1...