Given y = x^{lnx} find dy/dx using Logarithmic differentiation. 1) x^{lnx-1}(2 lnx) 2) x^{lnx}(2x lnx) 3) x^{lnx}(2 lnx) 4) x^{lnx}(lnx + 1)
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Step 1: Take the natural logarithm of both sides of the equation: \[ \ln(y) = \ln(x \ln(r)) \] Show more…
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