Question 5 In humans, freckles (F) is dominant to no freckles (f). What is the probability of having a child with freckles from a monohybrid cross? 0% 1/4 or 25% A monohybrid cross means that both parents are heterozygous. The cross for the Punnett square should be: Ff x Ff. Children with genotype FF or Ff have freckles. Children with genotype ff do not have freckles. 3/4 or 75% 1/2 or 50%
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The Punnett square would look like this: F f F FF Ff f Ff ff From this, we can see that there are four possible genotypes for the offspring: FF, Ff, Ff, and ff. Since freckles are dominant, both FF and Ff will result in freckles. Show more…
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