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Question 5 4 pts Evaluate ∫3^8 f(t)dt, where f(t) is continuous on [3,8], and F'(t)=f(t) and F(3)=2, and F(8)=7 14 -5 9 5

Name: question 5 4 pts evaluate 38 ftdt where ft is continuous on 38 and ftft and f32 and f87 14 5 9 5 94574
Uploaded: 2023-10-13T16:00:15-08:00
Duration: 3 min 42 s
Channel: Adi S
Description: question 5 4 pts evaluate 38 ftdt where ft is continuous on 38 and ftft and f32 and f87 14 5 9 5 94574

          Question 5
4 pts
Evaluate ∫3^8 f(t)dt, where f(t) is continuous on [3,8], and F'(t)=f(t) and F(3)=2, and F(8)=7
14
-5
9
5

Added by Robert G.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Adi S

10/13/2023

Step 1

Step 1: Since F'(t) = f(t), we can use the Fundamental Theorem of Calculus to evaluate the definite integral. Show more…

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Question 5 4 pts Evaluate ∫3^8 f(t)dt, where f(t) is continuous on [3,8], and F'(t)=f(t) and F(3)=2, and F(8)=7 14 -5 9 5

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Question 5 4 pts Evaluate ∫3^8 f(t)dt, where f(t) is continuous on [3,8], and F'(t)=f(t) and F(3)=2, and F(8)=7 14 -5 9 5

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