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Question 5 Consider the function f(x) = x^3 - 3x^2 + 3. Find the points where the tangent line is horizontal. a) (0, 0) (2, 0) b) (-1/2, 17/8) c) (0, 3) (2, -1) d) (-1/2, 17/8) (1/2, 19/8) e) (1/2, 19/8) (-1/2, 17/8) Question 6 Given the function f(x) = 1/3x^3 - x^2 + 2, find the points where the tangent line has slope 3. a) (-3, -16), (1, 4/3) b) (0, 2), (3, 2) c) (-3, -16), (-1, 2/3) d) (3, 2), (-1, 2/3) e) (0, 2), (1, 4/3)

          Question 5
Consider the function f(x) = x^3 - 3x^2 + 3. Find the points where the tangent line is horizontal.
a) (0, 0) (2, 0)
b) (-1/2, 17/8)
c) (0, 3) (2, -1)
d) (-1/2, 17/8) (1/2, 19/8)
e) (1/2, 19/8) (-1/2, 17/8)
Question 6
Given the function f(x) = 1/3x^3 - x^2 + 2, find the points where the tangent line has slope 3.
a) (-3, -16), (1, 4/3)
b) (0, 2), (3, 2)
c) (-3, -16), (-1, 2/3)
d) (3, 2), (-1, 2/3)
e) (0, 2), (1, 4/3)

Question 5
Consider the function f(x) = x^3 - 3x^2 + 3. Find the points where the tangent line is horizontal.
a) (0, 0) (2, 0)
b) (-1/2, 17/8)
c) (0, 3) (2, -1)
d) (-1/2, 17/8) (1/2, 19/8)
e) (1/2, 19/8) (-1/2, 17/8)
Question 6
Given the function f(x) = 1/3x^3 - x^2 + 2, find the points where the tangent line has slope 3.
a) (-3, -16), (1, 4/3)
b) (0, 2), (3, 2)
c) (-3, -16), (-1, 2/3)
d) (3, 2), (-1, 2/3)
e) (0, 2), (1, 4/3)

Added by Alba G.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Question 5 Consider the function f(x) = x^3 - 3x^2 + 3. Find the points where the tangent line is horizontal. a) (0,0) (2,0) b) (-1/2, 17/8) c) (0,3) (2,-1) d) (-1/2, 17/8) (1/2, 19/8) e) (1/2, 19/8) (-1/2, 17/8) Question 6 Given the function f(x) = 1/3x^3 - x^2 + 2, find the points where the tangent line has slope 3. a) (-3,-16), (1, 4/3) b) (0,2), (3,2) c) (-3,-16), (-1, 2/3) d) (3,2), (-1, 2/3) e) (0,2), (1, 4/3)