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Question 6: (20 marks - form Midterm Exam 2023) We wish to produce B in the reaction A?B in a CSTR at a volumetric rate of 4 liter/min with CA0 = 2 moles/liter. However, we find that there is a second reaction B ? C that can also occur. We find that both reactions are first order and irreversible with $k_1 = 0.5$ min$^{-1}$ and $k_2 = 0.1$ min$^{-1}$. To maximize the yield of B, find the following, i. Space time ii. Reactor volume iii. Selectivity of B and iv. Yield of B (maximum) \text{Selectivity} = \frac{\text{moles of desired product B formed}}{\text{moles of all products formed}} = \frac{C_B}{C_B + C_C} \text{Yield} = \frac{\text{moles of desired project B formed}}{\text{mole of reactant in the feed}} = \frac{C_B}{C_{A0}} CSTR Mole balance equation F_{A0} - F_A + r_AV = 0; \tau = \frac{V}{v} \text{ (space time)} Step-by-step derivation & calculation is required. A short-cut answer will bring no marks.

          Question 6: (20 marks - form Midterm Exam 2023)
We wish to produce B in the reaction A?B in a CSTR at a volumetric rate of 4 liter/min with
CA0 = 2 moles/liter. However, we find that there is a second reaction B ? C that can also occur.
We find that both reactions are first order and irreversible with $k_1 = 0.5$ min$^{-1}$ and $k_2 = 0.1$ min$^{-1}$.
To maximize the yield of B, find the following,
i.
Space time
ii.
Reactor volume
iii.
Selectivity of B and
iv.
Yield of B (maximum)
\text{Selectivity} = \frac{\text{moles of desired product B formed}}{\text{moles of all products formed}} = \frac{C_B}{C_B + C_C}
\text{Yield} = \frac{\text{moles of desired project B formed}}{\text{mole of reactant in the feed}} = \frac{C_B}{C_{A0}}
CSTR Mole balance equation
F_{A0} - F_A + r_AV = 0; \tau = \frac{V}{v} \text{ (space time)}
Step-by-step derivation & calculation is required. A short-cut answer will bring no marks.

Question 6: (20 marks - form Midterm Exam 2023)
We wish to produce B in the reaction A?B in a CSTR at a volumetric rate of 4 liter/min with
CA0 = 2 moles/liter. However, we find that there is a second reaction B ? C that can also occur.
We find that both reactions are first order and irreversible with k1 = 0.5 min^-1 and k2 = 0.1 min^-1.
To maximize the yield of B, find the following,
i.
Space time
ii.
Reactor volume
iii.
Selectivity of B and
iv.
Yield of B (maximum)
Selectivity = (moles of desired product B formed)/(moles of all products formed) = (CB)/(CB + CC)
Yield = (moles of desired project B formed)/(mole of reactant in the feed) = (CB)/(CA0)
CSTR Mole balance equation
FA0 - FA + rAV = 0; τ= (V)/(v) (space time)
Step-by-step derivation calculation is required. A short-cut answer will bring no marks.

Added by Curtis M.

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