00:01
Hello, in the question we have to find out the strength and the direction of the electric field at the position indicated by the dot.
00:08
So, this is the configuration we have this 1 nanocoulomb charge over here.
00:13
So now let us see due to the positive charge what is the electric field.
00:16
So the electric field due to this positive charge will be in this direction.
00:20
Let us call it as e1 and due to this minus 1 nanocoulomb this charge, this electric field will be in this direction.
00:28
So e1, let us calculate e1.
00:30
So, e1 will be equal to kq divided by r1 square.
00:36
I have written here what is r1 and what is r2.
00:39
So r2 we have just calculated by using the pythagoras theorem over here.
00:43
So it is in the positive x cap direction.
00:46
So e1 will be equal to 9 into 10 raised to 9 into q is 1 nanocoulomb.
00:53
So it will be 1 into 10 raised to minus 9 divided by r1 is 5 into 10 raised to minus 2 square of this in the x cap direction.
01:03
So if we calculate this, we will get e1 which is equal to 3600 newton per coulomb in the positive x cap direction.
01:14
Now e2, we will not specify the direction, but we will directly find the components.
01:19
So e2 will be kq divided by r2 square.
01:24
So k is 9 into 10 raised to 9 into q is 1 into 10 raised to minus 9.
01:33
So it is 10 raised to minus 9 divided by 5 root 5 into 10 raised to minus 2 and square of this quantity.
01:48
So if we calculate this, e2 will turn out to be 720 newton per coulomb.
01:57
Now see this e2, we can resolve the components in the x and y.
02:01
So we need this angle.
02:03
So we will use theta is equal to tan inverse of opposite upon adjacent.
02:11
So that is 10 by 5.
02:14
So if we calculate this angle, so theta will be 63 .43.
02:21
So e1, sorry e2, the x component, so e2x will be, if we calculate, so it will be e2 cosine of 63 .43.
02:34
So if we calculate this, we will get this answer as minus minus 322 .049 newton per coulomb...