00:01
In this question, we need to obtain the volume of a solid, whose base lies in the xy plane bounded by the curves y is equal to negative of 3x and y is equal to 4 minus x squared.
00:23
Whereas its top is given by the curve, z is equal to x plus 8.
00:32
Now, since the base lies in xxx plane and the top is x plus 8, therefore the limits of z are from 0 to x plus 8.
00:44
Also, from the base we can see that the limits of y are from negative of 3x to 4 minus x squared.
00:54
To obtain the limits of x, let us grasp the curves.
01:00
Y is equal to negative of 3x and 4 minus x squared.
01:05
The graph of these calls is given by this figure.
01:09
From the figure we can see that the limits, the x value starts from negative of 1 and goes till 4.
01:18
Therefore the limits of x are negative of 1 to 4.
01:23
Now using all these limits we can obtain the volume.
01:26
The volume of the region is given by integration from negative of 1 to 4, then along y, negative of 3x to 4 minus x squared, then z from 0 to x plus 8, times d z, d, d, d, d x.
01:53
Integrating we get v is equal to negative of 1 to 4, negative of 3x to 4 minus x squared times z from from 0 to x plus 8, t y d x...