Question content area top Part 1 Evaluate the following integral. Integral from 0 to 1 Integral from 0 to 3 minus 3 x Integral from 0 to 3 minus 3 x minus y dz dy dx
Added by Adam D.
Step 1
Step 1: First, let's evaluate the innermost integral with respect to z: Integral from 0 to 3 - 3x - y dz = (3 - 3x - y)z evaluated from 0 to 3 = (3 - 3x - y)(3) - (3 - 3x - y)(0) = 9 - 9x - 3y Show more…
Show all steps
Close
Your feedback will help us improve your experience
Carlos Pinilla and 76 other Calculus 1 / AB educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Evaluate the integrals. $$\int_{0}^{1} \int_{0}^{3-3 x} \int_{0}^{3-3 x-y} d z d y d x$$
Multiple Integrals
Triple Integrals in Rectangular Coordinates
Evaluate the integral by interpreting it in terms of areas. $$\int_{0}^{3}\left(\frac{1}{2} x-1\right) d x$$
Integrals
The Definite Integral
Evaluate the integral by interpreting it in terms of areas. $$\int_{-1}^{3}(3-2 x) d x$$
Recommended Textbooks
Calculus: Early Transcendentals
Thomas Calculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD