Question

Suppose that f is a function given as f(x) = 1 / (3x + 4). We will compute the derivative of f at x = 5 as follows. First, we compute and simplify the expression f(5 + h). f(5 + h) = Then we compute and simplify the difference quotient, between x = 5 and x = 5 + h. (f(5 + h) - f(5)) / h = The derivative of the function at x is the limit of the difference quotient as h approaches zero. f'(5) = lim_{h ? 0} (f(5 + h) - f(5)) / h =

          Suppose that f is a function given as f(x) = 1 / (3x + 4). We will compute the derivative of f at x = 5 as follows.

First, we compute and simplify the expression f(5 + h).
f(5 + h) =

Then we compute and simplify the difference quotient, between x = 5 and x = 5 + h.
(f(5 + h) - f(5)) / h =

The derivative of the function at x is the limit of the difference quotient as h approaches zero.
f'(5) = lim_{h ? 0} (f(5 + h) - f(5)) / h =

Suppose that f is a function given as f(x) = 1 / (3x + 4). We will compute the derivative of f at x = 5 as follows.

First, we compute and simplify the expression f(5 + h).
f(5 + h) =

Then we compute and simplify the difference quotient, between x = 5 and x = 5 + h.
(f(5 + h) - f(5)) / h =

The derivative of the function at x is the limit of the difference quotient as h approaches zero.
f'(5) = limh ? 0 (f(5 + h) - f(5)) / h =

Added by David M.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Vishal Parmar

08/01/2022

Step 1

Step 1:** Substitute x = 5 into the given function f(x) = 3 + 4x: \[ f(5) = 3 + 4(5) = 3 + 20 = 23 \] ** Show more…

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Suppose that f is a function given as f(x). We will compute the derivative of f at x = 5 as follows. First, we compute and simplify the expression f(5 + h). f(5 + h) Then we compute and simplify the difference quotient, between x = 5 and x = 5 + h. f(5 + h) - f(5) / h The derivative of the function at x is the limit of the difference quotient as h approaches zero. f'(5) = lim h->0 (f(5 + h) - f(5)) / h