Question 7 10 pts Note: please combine your solutions into one file before uploading it. A bipolar Wilson current mirror is shown the figure below. All transistors are identical with the current gain of $eta$. $V_{supp}$ is the DC supply voltage. Show that the current gain is: $frac{I_{out}}{I_{in}} approx 1 - frac{2}{eta^2 + 2eta + 2}$
Added by Marie S.
Close
Step 1
The expression for the current gain of a Wilson current mirror as given, Iout1 = 2 * Iin * (β + 2) / Vsupp, does not accurately represent the operation or the outcome of a Wilson current mirror circuit. The Wilson current mirror is a configuration used in analog Show more…
Show all steps
Your feedback will help us improve your experience
Adi S and 99 other Physics 102 Electricity and Magnetism educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
(II) A transistor, whose current gain $\beta = i_C/i_B = 65$, is connected as in Fig. 29-41 with $R_B = 3.8 \mathrm{k}\Omega$ and $R_C = 7.8 \mathrm{k}\Omega$ Calculate ($a$) the voltage gain, and ($b$) the power amplification.
MOLECULES AND SOLIDS
Transistors: Bipolar and MOSFETs
(II) A transistor, whose current gain $\beta=i_{C} / i_{B}=75,$ is connected as in Fig. 43 with $R_{B}=3.8 \mathrm{k} \Omega$ $R_{C}=7.8 \mathrm{k} \Omega$ . Calculate $(a)$ the voltage gain, and $(b)$ the power amplification.
A transistor, whose current gain $\beta=i_{\mathrm{C}} / i_{\mathrm{B}}=75,$ is connected as in Fig. $40-43$ with $R_{\mathrm{B}}=3.8 \mathrm{k} \Omega$ and $R_{\mathrm{C}}=7.8 \mathrm{k} \Omega .$ Calculate $(a)$ the voltage gain, and $(b)$ the power amplification.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD