00:01
A system of pooley has the following equation that is the model as the equation t1 minus 2t2, that is the t1, t2 are the tensions in t1 and t2 are the tensions in pounds and also age the acceleration in feet per second square.
00:21
So also we have given the second equation t1 minus 2a equals to 128 and the third is t2 plus a equals to 32.
00:35
So now we have to solve for t1, t2 and a.
00:37
So for this, see from the third equation we get t2 equals to 32 minus a.
00:43
Now put this value.
00:45
So t1 minus 2 multiplied with, so this is the first equation, minus multiplied with 32 minus a equals to 0, will give t1 and this will be the plus 2.
01:01
And we'll give here plus 64 and now the first is t1 plus 2a this is the minus 2a minus 2a equals to 128 and now by solving we get adding simply that is 2 t1 equals to this will be the 8 412 and 6 to 8 and 9 and this is 192 so that means t1 so that is t1 equals to 192 divide with 2 that means 96.
01:39
So t1 equals to 96.
01:41
That means now we have to solve for the t2...
