\int \frac{3x^2 - 1}{(x^3 - x)^2} dx = \\ A. \frac{-6x^2}{(x^3 - x)^3} + C \\ B. \frac{1}{3}(x^3 - x)^{-1} + C \\ C. \frac{-2}{(x^3 - x)^3} + C \\ D. \ln(x^3 - x)^2 + C \\ E. \frac{-1}{(x^3 - x)} + C
Added by Amber C.
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Step 1
We have S = 3x² - 1 and da/dx = (x³ - x)². So, we can rewrite the expression as S(da/dx) = (3x² - 1)(x³ - x)². Show more…
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