Say that f:A->B is a function where A and B are both subsets of N. If |B| > |A|, then you can conclude which of the following? a. f is not onto b. f is not one-to-one c. the cardinality of B is greater than or equal to the cardinality of the range of f
Added by Kenneth T.
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Step 1: Given that |B| > |A|, we can conclude that the function f is not onto, as the cardinality of B is greater than the cardinality of A, meaning there are elements in B that are not mapped to by any element in A. Show more…
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