Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: A = {1,2,3,4,5,6} Codomain: B = {w, x, y, z} f = {(3,w), (4,z), (1,z), (6,w), (5x), (2,x)}
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Injective (one-to-one): A function is injective if every element in the domain is mapped to a unique element in the codomain. In other words, no two elements in the domain have the same image in the codomain. Let's check if the given function is injective: f(3) = Show more…
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Say whether the following function is injective, surjective, bijective, or none of the above (note: you can only select one option): Domain: A = {1, 2, 3, 4, 5, 6} Codomain: B = {w, x, y, z} f = {(3, w), (4, z), (1, z), (6, w), (5, x), (2, x)}
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Consider the following function f. f('g')= 6 f('h')= 1 f('i')= 8 f('j')= 4 f('k')= 5 f('l')= 8 f('m')= 6 f('n')= 4 Recognizing that this function has a domain of {'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n'} and a codomain of {1, 4, 5, 6, 8}, which of the following is true? Select one: a. f is injective, but not surjective b. f is bijective c. None of the above d. f is surjective, but not injective
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