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Score on last try: 0.5 of 1 pts. See Details for more. > Next question Get a similar question You can retry this question below If $f(x) = 3 \sin x + 2 \cos x$, then $f'(x) = 3 \cos(x) \quad 2 \sin(x)$ f'(1) = 2.96463827 Question Help: Message instructor Add Work Calculator Submit Question

          Score on last try: 0.5 of 1 pts. See Details for more.
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If $f(x) = 3 \sin x + 2 \cos x$, then
$f'(x) = 3 \cos(x) \quad 2 \sin(x)$
f'(1) = 2.96463827
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Score on last try: 0.5 of 1 pts. See Details for more.
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If f(x) = 3 sin x + 2 cos x, then
f'(x) = 3 cos(x) 2 sin(x)
f'(1) = 2.96463827
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Added by Eduardo C.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Yujie Wang

07/04/2022

Step 1

The derivative of sinx is cosx, and the derivative of cosx is -sinx. Therefore, the derivative of f(x) = 3sinx + 2cosx is f'(x) = 3cosx - 2sinx. Show more…

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Score on last try: 0.5 of 1 pts. See Details for more. Next question Get a similar question You can retry this question below If f(x)=3sinx+2cosx, then f'(x)= 0^(6) f'(1)= Question Help: Message instructor Add Work Score on last try 0.5 of 1 pts. See Details for more Next question Get a similar question You can retry this question below If f=3sin2cos then f' = 3cos2sin f(1)= 2.96463827 + Question Help: Message instructor Add Work Calculator Submit Question