Show how you would prepare 2 mL of a 10% solution (#S) of blue food-color dye in a test tube. Put 0.9 mL H2O into each of ten new test tubes. Label five of the tubes 1 through 5 and the other five A through E. In tubes 1-5, you prepared a two-fold serial dilution of your 10% dye solution (#S) by doing the following. Calculate the dye concentration in each tube. i.e. #1: (0.9 mL #S + 0.9 mL H2O) = #2: (0.9 mL #1 + 0.9 mL H2O) = #3: (0.9 mL #2 + 0.9 mL H2O) = #4: (0.9 mL #3 + 0.9 mL H2O) = #5: (0.9 mL #4 + 0.9 mL H2O) =
Added by Barbara J.
Step 1
In tube 1, the dye concentration is 0.9 ml (#S + 0.9 ml H2O). In tube 2, the dye concentration is 1.1 ml (#1 + 0.9 ml H2O). In tube 3, the dye concentration is 1.4 ml (#2 + 0.9 ml H2O). In tube 4, the dye concentration is 1.7 ml (#3 + 0.9 ml H2O). In tube 5, the Show more…
Show all steps
Your feedback will help us improve your experience
Sri K and 54 other Biology educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Sri K.
You prepare a 10 mL 10% (by volume) dye solution of 1 M crystal violet dye and water in a 100 mL volumetric flask. a) If you were to dilute your original solution down to 1.0 part per billion (ppb), what would be the molar concentration (M) of the dye in this solution? b) Approximately how many dye particles would be in 1.0 mL of this solution? c) Approximately how many water molecules would be in 1.0 mL of this solution? (Use the density of water as 1.0 g/mL and the volume of the solution equal to the volume of water.) d) What is the ratio of water molecules to one dye particle? e) Using the ratio you calculated in part (d), what is a real-world comparison you can make to help you understand the ratio of solute (dye) particles to solvent (water) molecules? f) Thinking about the comparison you made in (e), approximately how far apart are the dye particles in this solution?
A student makes the following series of dilutions, beginning with a concentrated solution of red dye. Dilution #1: 1 ml concentrated dye + 4 ml water (makes 5 ml total) Dilution #2: 1 ml Dilution #1 + 4 ml water (makes 5 ml total) Dilution #3: 1 ml Dilution #2 + 9 ml water (makes 10 ml total) Dilutions #1 and #2 are both ____-fold dilutions for a combined dilution of ____-fold. Dilution #3 is a ____-fold dilution., so that altogether the red dye has been diluted ____-fold. If the concentrated dye that the student started with was at a concentration of 10-4 M, at the end the concentration will be ____M.
Dominador T.
Recommended Textbooks
Biology for AP Courses
Objective Biology for NEET
Introduction to General, Organic and Biochemistry
Transcript
200,000+
Students learning Biology with Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD
