Sketch the following curve, indicating all relative extreme points and inflection points. y = 8 - 3x^2 - x^3 The relative extreme points are (Type an ordered pair. Use a comma to separate answers as needed.)
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The derivative of y = 8 - 32 - x^3 is given by: dy/dx = -3x^2 To find the critical points, we set the derivative equal to zero and solve for x: -3x^2 = 0 This equation has only one solution, x = 0. Now, let's find the second derivative to determine the Show more…
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