00:01
For this problem, you have to refer to the graph that's given.
00:05
They give you a position versus time graph and ask you to sketch the velocity versus time graph.
00:11
I'm going to break up the get graph that's given into one, two, three, four, five different segments.
00:16
You want to find the slope for each because that'll give you the velocity for each of those segments.
00:20
It's five different constant velocities the graph transitions through.
00:25
So coordinates for the first segment zero zero and point four, four.
00:34
It's in meters and seconds.
00:37
So change in y over change in x, the slope or the velocity for this first segment is going to be change in y 4 minus 0 over 0 .4.
00:47
So 4 over 0 .4.
00:50
When you divide that out, 4 divided by 0 .4 is equal to 10.
00:58
So 10 meters per second positive for the first segment meters per second.
01:03
And that goes out to 0 .4 seconds.
01:07
So it's moving at that speed for that amount of time.
01:11
For segment b, it starts at 0 .44, and it ends at 0 .6 negative 2.
01:23
So v would be changing y, negative 2, minus 4 over 0 .6 minus 0 .4.
01:35
You get negative 6 over 0 .2.
01:37
Divide that out and you get 30 negative 30 meters per second that interval is from 0 .4 seconds out to 0 .6 seconds so you need to keep track of that as you're going along here for c starts at 0 .6 negative 2 and it ends at 1 negative 6 so the velocity is going to be changing y negative 6 minus minus minus 2 over 1 minus 0 .6.
02:19
So that is going to be plus positive.
02:22
You're going to get negative 4 over 0 .4, which is going to be negative 10 meters per second.
02:30
It's doing that from 0 .6 out to 0 .6 out to 1.
02:38
Segment d, 1, negative 6.
02:43
It ends at 1 .6 negative 4.
02:51
Change in y for the sorry for the velocity you're going to do negative 4 minus minus 6 over negative that shouldn't be negative 1 .6 sorry that's positive let me erase that real quick if i can this negative does not belong so it doesn't belong here either so 1 .6 minus 1 you get plus positive 2 divided by 0 .6.
03:37
2 divided by 0 .6 is 3 .33 meters per second.
03:45
That is from 1 out to 1 .6.
03:54
That's the time frame.
03:56
And finally, e, 1 .6 to negative 4, 1 .6, negative 4, sorry, 2, 2.
04:05
2.
04:08
So, v is equal to change in y.
04:12
This would be 2 minus 4 over 2 minus 1 .6.
04:21
So it goes plus positive again.
04:23
So this is 6 over 0 .4.
04:28
6 divided by 0 .4 is 15, positive 15.
04:36
That's happening from 1 .6 seconds out to 2 seconds.
04:41
So in my graph, i've got to plot it out so that i can fit 2 seconds on there, up to 2 seconds.
04:46
So that means about halfway through is going to be one...