00:01
Okay, what i answer this question is talk about hard on the grammar equilibrium.
00:03
We're going to according to that, p plus q is going to be equal to one, where p is the frequency of the dominant allele, if it means like this, and q is the frequency of a digressif alil in this population.
00:14
While p square plus 2pq plus q is equal to 1, where p square is the frequency of individuals in this population of homosego.
00:24
2 pq is the frequency of individuals in the population that are heterocygose, and q is the frequency of individuals in this population.
00:30
That are homozygo recessive.
00:32
Okay? this question says cystic fibrosis is an autosomer recessive disorder that affects one out of one, out of two thousand newborn americans.
00:44
A woman without cystic fibrosis and no family history of the disease was to know the likelihood that she carries the disease allele.
00:51
So, it says using the hardware equilibrium equation like this, what is the probability that she is a carrier? so practically we have to work with this.
01:01
This is the frequency for 65 bros.
01:04
It means positive and this is also the value for q squared.
01:07
So you have the q squared is equal to 1 divided by 2 ,000.
01:12
You can divide this and you're going to get that qs square is equal to 0 .005.
01:22
So you can apply a good square at both sides and you're going to get that approximately the value for q is going to be 0 .22.
01:31
Oh, i'm forget, 0 .0 .0...