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Solve the given initial-value problem.\\ $X' = \begin{pmatrix} 4 & -1\\ 5 & 2 \end{pmatrix} X$, $X(0) = \begin{pmatrix} -4\\ 6 \end{pmatrix}$\\ $x(t) = (-2e^{3t} + 3e^{3t}cos (2t) - 2e^{3t}sin (2t))$

          Solve the given initial-value problem.\\
$X' = \begin{pmatrix} 4 & -1\\ 5 & 2 \end{pmatrix} X$, $X(0) = \begin{pmatrix} -4\\ 6 \end{pmatrix}$\\
$x(t) = (-2e^{3t} + 3e^{3t}cos (2t) - 2e^{3t}sin (2t))$

Solve the given initial-value problem.

X' =
< p m a t r i x >
X, X(0) =
< p m a t r i x >

x(t) = (-2e^3t + 3e^3tcos (2t) - 2e^3tsin (2t))

Added by Carrie M.

Calculus: Early Transcendentals

James Stewart 8th Edition

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Solve the given initial-value problem. \[X(t) = 2e + 3e^{3t}\cos(2t) - 2e^{3t}\sin(2t)\]

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Question

Solve the given initial-value problem.\\ $X' = \begin{pmatrix} 4 & -1\\ 5 & 2 \end{pmatrix} X$, $X(0) = \begin{pmatrix} -4\\ 6 \end{pmatrix}$\\ $x(t) = (-2e^{3t} + 3e^{3t}cos (2t) - 2e^{3t}sin (2t))$

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