Question

Solve the initial value problem\\ with $x(0) = 1$.\\ x(t) = \\ \frac{dx}{dt} - 4x = cos(4t)

          Solve the initial value problem\\
with $x(0) = 1$.\\
x(t) = \\
\frac{dx}{dt} - 4x = cos(4t)

Solve the initial value problem

with x(0) = 1.

x(t) =

(dx)/(dt) - 4x = cos(4t)

Added by Stephanie P.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Zhumagali Shomanov

06/15/2022

Step 1

The standard form of a first-order linear differential equation is given by: dy/dx + P(x)y = Q(x) In this case, we have: dx - 4x = cos(4t) So, we can rewrite the equation as: dx - 4x = cos(4t) Show more…

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Solve tha initial value problem dx-4x=cos4t wth0=1 0=

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Solve the initial value problem\\ with $x(0) = 1$.\\ x(t) = \\ \frac{dx}{dt} - 4x = cos(4t)

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