2) The Laplace Transform $\mathcal{L}\{e^{-t^2}\}$ exists, but without finding it, solve the given IVP $y'' + y = e^{-t^2}$, $y(0) = 0$, $y'(0) = 0$.
Added by Richard J.
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The given equation is y + y' = 0. We can rewrite it as y' = -y. Show more…
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