Solve the given problems. The sum $S$ of the measures of the interior angles of a polygon with $n$ sides is $S=180(n-2) .$ (a) Solve for $n .$ (b) If $S=3600^{\circ},$ how many sides does the polygon have?
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Step 1
(a) To solve for $n$, we can rearrange the formula to get: $$n=\frac{S}{180}+2$$ (b) Substituting $S=3600^\circ$ into the formula from part (a), we get: $$n=\frac{3600}{180}+2=22$$ Show more…
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