Solve the initial value problem, (1/x + 2y^2x) dx + (2yx^2 - cos y) dy = 0, with y(1) = ??.

Name: Solve the initial value problem, (1/x + 2y^2x) dx + (2yx^2 - cos y) dy = 0, with y(1) = ??.
Uploaded: 2023-04-19T00:36:53-08:00
Duration: 2 min 43 s
Channel: Numerade
Description: Solve the initial value problem, (1/x + 2y^2x) dx + (2yx^2 - cos y) dy = 0, with y(1) = ??.

Question

Adi S · Answer

We are given a equation 1 by x plus 2y square x into dx plus here 2y x square minus cos of y dy

Sri K · Answer

So, consider the equation 1 divided by x plus 2 y square x dx plus 2 y x square minus cos y dy e

Adi S · Answer

Derivative of y with respect to x is equal to xy square minus cos x sin x divided by y 1 minus x

Adi S · Answer

Derivative of y with respect to x is equal to xy square minus cos x sin x divided by y 1 minus x

Suman K · Answer

In this question, given that x plus 2 whole square, D .Y of D x is equal to 5 minus 8y minus 4 x

Question

Solve the initial value problem, (1/x + 2y^2x) dx + (2yx^2 - cos y) dy = 0, with y(1) = ??.

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