00:01
In this question we are given that suppose a box contains 10 defective batteries and 18 good battery.
00:07
So let us denote defective battery by d and good batteries by capital g.
00:12
And we have to pick two batteries from the box without any replacement.
00:18
Now in first part, we are asked the probability that first one is good and second one is defective.
00:25
So required probability will be first one will be good.
00:29
That is probability of good battery multiplied by probability of second battery is defective so p d so required probability that is p equal to now if first one is good then probability of this will be 18 divided by now total number of batteries will be 28 in starting so this will divide by 28 multiplied by 10 divided by now we have not done any replacement so now total number of batteries will be 27 so, when we solve this, we get 2 multiplied by 10 divided by 18 multiplied by 3.
01:09
So on solving, we get 5 divided by 7 multiplied by 3.
01:16
So, total required probability will be 5 divided by 21.
01:22
So this is our answer of part a.
01:26
Now, coming to the part b...