00:01
In this problem, they are provided with the differential equation y double dash plus 4 times y dash plus 13 times y equals to 0 and we are also given that its general solution is y equals to e raised to the power negative 2x times c1 times sine of 3x plus c2 times cost of 3x where c1 and c2 are arbitrary constants.
00:31
We are provided with the initial conditions at y of 0 equals to negative 2 and y dash of 0 equals to negative 5.
00:40
We are asked to find out a specific solution of y.
00:45
So now for this let us make use of the initial condition.
00:49
We have x equals to 0 and y equals to negative 2.
00:53
Let us substitute this in a general solution.
00:56
We get negative 2 equals 2.
00:58
E raised to the power of negative 2 times 0 times c1 sign of 3 times 0 which is 0 plus c2 cost of 3 times 0 which is 0.
01:12
Further simplifying this we have negative 2 equals to e power 0 is 1, sign of 0 is 0 and cost of 0 is 1.
01:23
So we see that c1 times cosine of 0 which is 0 equals to 0 itself and c2 times 1 gives us c2.
01:34
So we get the value of c2 to be negative 2.
01:38
Now let us make use of the second initial condition.
01:41
So for the second initial condition we require the first derivative of y.
01:45
So let us differentiate the general solution...