Suppose that f and g are functions that are differentiable at x = 1 and that f(1) = 2, f '(1) = -2, g(1) = -2, and g'(1) = 2. Find h'(1). h(x)=( f(x)g(x))/(f(x)-g(x)) h'(1)=
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Step 1
Step 1: Calculate the numerator of h'(1) using the given values: Numerator = (f(1) * g'(1) + g(1) * f'(1)) - (f(1) * g(1) * (f'(1) - g'(1))) Numerator = (2 * 2 + (-2) * (-2)) - (2 * (-2) * (-2 - 2)) Numerator = (4 + 4) - (-8) Numerator = 8 + 8 Numerator = 16 Show more…
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