Suppose that the function $f$ is defined, for all real numbers, as follows. $$f(x) = \begin{cases} \frac{3}{4}x-2 & \text{if } x \neq 2 \\ 2 & \text{if } x = 2 \end{cases}$$ Find $f(-3)$, $f(2)$, and $f(4)$. $f(-3) = $ $f(2) = $ $f(4) = $
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Step 1: Since $-3 \neq 2$, we use the first part of the definition of $f$ to find $f(-3)$. Show more…
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