Table I. Folin-Lowry Protein Standard Curve: Lysozyme (1.0 mg/mL) and bovine serum albumin (BSA, 1.0 mg/mL) are used to prepare standard curve. All determinations must be in duplicate and plot the mean value for each data point. Final volume is 5.0 mL. 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 Tube Number | Water mL | 1mg/mL Lysozyme mL in assay | Reagent A mL | Reagent B mL | Reagent C mL | mg Protein (lysozyme) | ABS at 650 nm 1A | 1.0 | 0 | 0.9 | 0.1 | 3.00 | | Use to zero 2A | 0.99 | 0.01 | 0.9 | 0.1 | 3.00 | | 0.15 3A | 0.98 | 0.02 | 0.9 | 0.1 | 3.00 | | 0.19 4A | 0.96 | 0.04 | 0.9 | 0.1 | 3.00 | | 0.30 5A | 0.92 | 0.08 | 0.9 | 0.1 | 3.00 | | 0.46 6A | 0.84 | 0.16 | 0.9 | 0.1 | 3.00 | | 0.78
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First, we need to calculate the concentration of lysozyme in each tube. Since the final volume is 5.0 mL, we can use the formula: Concentration of lysozyme = (Lysozyme mL / 5.0 mL) * 1.0 mg/mL Show more…
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Table I. Folin-Lowry Protein Standard Curve: Lysozyme (1.0 mg/mL) and bovine serum albumin (BSA, 1.0 mg/mL) are used to prepare standard curve. All determinations must be in duplicate and plot the mean value for each data point. Final volume is 5.0 mL. Tube Number Water mL 1mg/mL Lysozyme mL in assay Reagent A mL Reagent B mL Reagent C mL mg Protein (lysozyme) ABS at 650 nm
Jenny W.
2. Protein Assays (20 points) You performed the Lowry assay to measure protein concentration of an unknown protein sample. You generated a standard curve using Bovine Serum Albumin (BSA) at a range of known concentrations (see below). Using this standard curve, calculate the concentration and amount of protein (in g) in each of your unknown samples (absorbances below).
Angela W.
A Biuret assay was run using albumin standards and an unknown protein. The albumin standard was 20 mg/1 mL. Construct a standard curve (please include your graph when you turn in your quiz) and calculate how many mg/1 mL are in the unknown. Show all your work. Standard, mL albumin standard, mL water, Absorbance 1, 0.00, 1.00, 0.00 2, 0.10, 0.90, 0.210 3, 0.15, 0.85, 0.295 4, 0.20, 0.80, 0.400 5, 0.40, 0.60, 0.780 6, 0.50, 0.50, 0.995 7, 0.60, 0.40, 1.230 8, 0.70, 0.30, 1.400 9, 0.80, 0.20, 1.580 10, 1.00, 0.00, 1.990 Two tubes were run with the unknown. One contained 1.0 mL of the unknown and 0 mL of water; it had an absorbance of 0.700. The other tube contained 0.5 mL of the unknown and 0.5 mL of water; it gave an absorbance of 0.390.
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