Table 1: Mendel's Traits and Symbols for Pea Plants Traits...

Table 1: Mendel's Traits and Symbols for Pea Plants Traits Dominant Allele Symbol Recessive Allele Symbol Seed Shape Round R Wrinkled r Seed Color Yellow Y Green y Pod Shape Smooth S Constricted s Pod Color Green G Yellow g Plant Height Tall T Short t Flower Position Axial A Terminal a Refer back to Table 1 on the first page of this assignment to answer the following two questions. Use the appropriate symbols and phenotypes in your answer. 1. Show the genotypes of the parents in the following crosses (2): a) A plant with green, wrinkled seeds is crossed with a plant that is known to be heterozygous for both seed color and seed shape: b) A plant that is heterozygous tall with terminal flowers is crossed with a plant that is short with homozygous axial flowers: 2. For the following two-trait cross: - Make a Punnett square to determine the possible genotype outcomes for this cross. - State the phenotype and genotype ratios of the offspring. (2 points) Parental genotypes: Ggss x ggSs

Transcript

00:01 Hello students in this question we have given a table and in the question number one we have to tell the genotype of the pair -aid where a plant with green wrinkle seed is crossed with a plant that is known to be heterozygous for both seed color and seed shape so answer for the a part is plant with green and wrinkle seeds it has genotype which will be both small white and small r because the alleys for both green and green seed color it is white and wrinkle seed shape it is small r which is a recessive and can be expressed homozygous condition and the plant that is hetrozygous for both trait it has genotype capital y small y capital r small r because in hetrozygous condition there will be one and one recessively for each tree.

01:43 So answer for the first question is the parents will have y, y, rr, recessive, homozygous recessive and this hettozygous.

01:55 Now in the b part, we have to tell the genotype of the parents who have a plant with hettozygous tall with terminal is crossed with a plant that has a shot with homozygous ed.

02:09 Axial flowers.

02:11 So the plant that is heterozygous stall with the terminal flower, it will have the genotype, capital t, small t and both small a.

02:41 So this will be genotype for heterozycous tall because the tollness allele, they are heterocycous and terminal plant, they are formed by recessive allele.

02:51 And the plant that is short and has homozygous axiolars they have the genotype both small t and both capital a because the short plant are formed by recessive allele and the allele for axial flower these are homozoidus so these are the genotype for the parents now in the question number 2, for apad we have to tell, by making a ponet square, we have to determine the genotype.

03:48 So let's see here, the parent's genotype which are capital g, small g and small s, both small g, capital s, small s.

04:04 So the possible gametes from this will be capital g small s and small g smallest and from this it will be small g, capital s.

04:18 And both small.

04:19 So let's perform this cross in a bonnet square.

04:35 So we have the gametes, capital and small.

04:42 So this will give capital g, small g, capital is smallest.

04:47 And small g both capital is, small is.

04:51 Capital g, small g and both small is all small...

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