Question

7, 8 and 9 Find the length of the curve correct to four decimal places. (Use a calculator to approximate the integral.) 7. $r(t) = (t^2, t^3, t^4)$, $0 < t \le 2$ Answer 8. $r(t) = (t, e^t, te^{-t})$, $1 \le t \le 3$ 9. $r(t) = (\cos \pi t, 2t, \sin 2\pi t)$, from $(1, 0, 0)$ to $(1, 4, 0)$

          7, 8 and 9 Find the length of the curve correct to four decimal places. (Use a calculator to approximate the integral.)
7. $r(t) = (t^2, t^3, t^4)$, $0 < t \le 2$
Answer
8. $r(t) = (t, e^t, te^{-t})$, $1 \le t \le 3$
9. $r(t) = (\cos \pi t, 2t, \sin 2\pi t)$, from $(1, 0, 0)$ to $(1, 4, 0)$

7, 8 and 9 Find the length of the curve correct to four decimal places. (Use a calculator to approximate the integral.)
7. r(t) = (t^2, t^3, t^4), 0 < t ≤ 2
Answer
8. r(t) = (t, e^t, te^-t), 1 ≤ t ≤ 3
9. r(t) = (cosπ t, 2t, sin 2π t), from (1, 0, 0) to (1, 4, 0)

Added by Alvaro Y.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Madhur L

04/26/2023

Step 1

Step 1: For the first problem, we are given the equation √t = t^2 and we need to find the length of the curve from t0 to 2. Show more…

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Texts: 8 only 7.8 and 9 Find the length of the curve correct to four decimal places (Use a calculator to approximate the integral.) 7. √t = t^2, t0 < t < 2 [Answer] 8. √t = t, e^(-t) - e^(-1) < t < 3 9. √t = cos(xt), 2t, sin(2√t) from 1, 0, 0 to 1, 4, 0