A particle is released as part of an experiment. Its speed t seconds after release is given by v(t) = -0.3t\textsuperscript{2} + 6t, where v(t) is in meters per second. a) How far does the particle travel during the first 6 sec? b) How far does it travel during the second 6 sec? a) The particle travels meters in the first 6 sec. (Round to two decimal places as needed.) b) The particle travels meters in the second 6 sec. (Round to two decimal places as needed.)
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The problem gives us the speed of a particle as a function of time, \(v(t) = -0.3t^2 + 6t\), and asks us to find how far the particle travels in the first 6 seconds and then how far it travels in the next 6 seconds (from 6 to 12 seconds). Show more…
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