Question

For the function $y = f(x) = x^2 - 3x + 3$, $x \ge 1.5$, find $\frac{df^{-1}}{dx}$ at $x = 11$. $(f^{-1})'(11) = $

          For the function $y = f(x) = x^2 - 3x + 3$, $x \ge 1.5$, find $\frac{df^{-1}}{dx}$ at $x = 11$.
$(f^{-1})'(11) = $

For the function y = f(x) = x^2 - 3x + 3, x ≥ 1.5, find (df^-1)/(dx) at x = 11.
(f^-1)'(11) =

Added by Judy H.

Calculus: Early Transcendentals

James Stewart 8th Edition

Instant Answer

Solved by Expert Ashley Volpe

06/08/2020

Step 1

To find the inverse function of f(x), we need to switch the roles of x and y in the equation y = x² - 3x + 3 and solve for y. x = y² - 3y + 3 Rearranging the equation, we get: y² - 3y + (3 - x) = 0 Using the quadratic formula, we can solve for y: y = (3 ± Show more…

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Texts: For the function y = f(x) = x² - 3x + 3, x ≥ 1.5, find (f⁻¹)'(11) = d(f⁻¹)/dx at x = 11. For the function y = f(x) = x² - 3x + 3, x ≥ 1.5, find d(f⁻¹)/dx at x = 11.