Question

The answer above is NOT correct. (1 point) Suppose $q(t)$ is a quantity function and $r(t)$ is the associated rate function. Consider the following table of values for $q(t)$ near the input $t = 0.0027$. \begin{array}{|c|c|c|c|c|c|} \hline t & -1 & -0.65967676 & -0.32848838 & 0.0027 & 0.33388838 & 0.66507676 \\ \hline q(t) & -0.99849324 & -0.097191271 & -0.33118838 & 0.14605544 & 0.99774223 \\ \hline \end{array} To obtain more precise information about the value of $q$ near $t = 0.0027$, you may enter a new increment value for $t$ here 0.33118838 Use the central difference approximation to estimate the value of $r(0.0027)$ to two significant figures of accuracy. $r(0.0027) = $ 0.40 NOTE: If your attempt is incorrect, you may need to try a new increment value for $t$ above. and then press the Submit Answer button.

          The answer above is NOT correct.
(1 point) Suppose $q(t)$ is a quantity function and $r(t)$ is the associated rate function.
Consider the following table of values for $q(t)$ near the input $t = 0.0027$.
\begin{array}{|c|c|c|c|c|c|}
\hline
t & -1 & -0.65967676 & -0.32848838 & 0.0027 & 0.33388838 & 0.66507676 \\
\hline
q(t) & -0.99849324 & -0.097191271 & -0.33118838 & 0.14605544 & 0.99774223 \\
\hline
\end{array}
To obtain more precise information about the value of $q$ near $t = 0.0027$, you may enter a new increment value for $t$ here 0.33118838
Use the central difference approximation to estimate the value of $r(0.0027)$ to two significant figures of accuracy.
$r(0.0027) = $ 0.40
NOTE: If your attempt is incorrect, you may need to try a new increment value for $t$ above. and then press the Submit Answer button.

The answer above is NOT correct.
(1 point) Suppose q(t) is a quantity function and r(t) is the associated rate function.
Consider the following table of values for q(t) near the input t = 0.0027.

t -1 -0.65967676 -0.32848838 0.0027 0.33388838 0.66507676

q(t) -0.99849324 -0.097191271 -0.33118838 0.14605544 0.99774223

To obtain more precise information about the value of q near t = 0.0027, you may enter a new increment value for t here 0.33118838
Use the central difference approximation to estimate the value of r(0.0027) to two significant figures of accuracy.
r(0.0027) = 0.40
NOTE: If your attempt is incorrect, you may need to try a new increment value for t above. and then press the Submit Answer button.

Added by Luc-A G.

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