The answer of the following integral: $I = \int_0^\infty xe^{-4x}dx$ is (remember to use limits.) 1/4 1/16 -(1/16) -(1/4)
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To do this, we can use the power rule for integration, which states that the integral of x^n dx = (1/(n+1))x^(n+1) + C, where C is the constant of integration. In this case, we have f(x) = re^(4x), so we can rewrite it as f(x) = r(e^4)^x. Now, using the power Show more…
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