Given:
Charge Q = 1.00 nC = $1.00 \times 10^{-9}$ C
Distance d = 5.60 cm = 0.056 m
$k = 9 \times 10^9$ Nm²/C²
Using the formula for electric field:
$E = \frac{Q}{4\pi\epsilon_0 d^2}$
Substitute the values:
$E = \frac{1.00 \times 10^{-9}}{4\pi \times 9 \times
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